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2x^2+11x=154
We move all terms to the left:
2x^2+11x-(154)=0
a = 2; b = 11; c = -154;
Δ = b2-4ac
Δ = 112-4·2·(-154)
Δ = 1353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1353}}{2*2}=\frac{-11-\sqrt{1353}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1353}}{2*2}=\frac{-11+\sqrt{1353}}{4} $
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